Today we focused on the ambiguous case of the sine law. A tricky little situation when we are using the sine law to solve for an angle of a triangle and we actually get two solutions!
This is kind of like when solving x^2 = 4 and we have two solutions: x = 2 and x = -2. You will see more of this when I teach you about quadratics! Anyway, back to trigonometry...
This is based off of part of section 2.3 of your text book.
#6, 8, 11, 24
Also get caught up on the rest of your homework!!
Hint: This is related to why there is no ambiguity in the obtuse case.