## Daily Overview

Hello Folks,

Today we focused on the ambiguous case of the sine law. A tricky little situation when we are using the sine law to solve for an angle of a triangle and we actually get two solutions!

This is kind of like when solving x^2 = 4 and we have two solutions: x = 2 and x = -2. You will see more of this when I teach you about quadratics! Anyway, back to trigonometry...

Today we focused on the ambiguous case of the sine law. A tricky little situation when we are using the sine law to solve for an angle of a triangle and we actually get two solutions!

This is kind of like when solving x^2 = 4 and we have two solutions: x = 2 and x = -2. You will see more of this when I teach you about quadratics! Anyway, back to trigonometry...

**This is based off of part of section 2.3 of your text book.**## GeoGebra Applets

## Homework

Do the following problems from Section 2.3 of your text book, pages 108 - 113:

#6, 8, 11, 24

#6, 8, 11, 24

**Also get caught up on the rest of your homework!!**## Challenge Puzzle

Pretend that the sine law (or a law like it) was stated using cosine instead of sine. Could there exist an ambiguous case? Why or why not?

*Hint: This is related to why there is no ambiguity in the obtuse case.*